Kenny Vermeers kirjoitti 11.05.2017 klo 12:12:

> In order to do this I need the splines dx/dt and dy/dt,. I was going to

> do this as follows

> tck, u = interpolate.splprep([x, y])

> dspl = interpolate.splder(tck)

> hoping to get dx/dt and dy/dt and then solving the integral.

> Unfortunately that doesn't work since splder doesn't seem to accept

> parametric splines. Do you have any suggestions on how to get the spline

> parameter from 0 to arclen?

You can grab the x(u) and y(u) splines from the output of splprep. It is

a bit ugly because splprep has a different padding convention than splrep.

t, c, k = tck

cx = np.concatenate([c[0], np.zeros(len(t) - len(c[0]))])

cy = np.concatenate([c[1], np.zeros(len(t) - len(c[1]))])

tck_x = (t, cx, k)

tck_y = (t, cy, k)

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